(500-50x-40x+4x^2)*x
最好有steps la~
[[急!!20分ga]] F.2 Mathz 1題 (super easy)
2007-01-19 5:28 am
回答 (5)
2007-01-19 6:35 pm
如果要簡化...
就要將有關係既數一組一組咁計...
↓...........
原式
=(500-90x+4x^2 )* x
利用乘法分配率↓
=500x-90x^2+4x^3
再一次利用乘法分配率...
=2x*(250-45x-2x^2)
就要將有關係既數一組一組咁計...
↓...........
原式
=(500-90x+4x^2 )* x
利用乘法分配率↓
=500x-90x^2+4x^3
再一次利用乘法分配率...
=2x*(250-45x-2x^2)
參考: 自已
2007-01-19 5:40 am
(500-50x-40x+4x^2)*x
=(4x^2-90x+500)*x
=2x(2x^2-45x+250)
=2x(2x-25)(x-10)
=(4x^2-90x+500)*x
=2x(2x^2-45x+250)
=2x(2x-25)(x-10)
2007-01-19 5:33 am
你要求咩ga??
係5係咁呀??
40x^3-90x^2+500x
係5係咁呀??
40x^3-90x^2+500x
2007-01-19 5:32 am
係咪factorize？
(500-50x-40x+4x2)x
=[(50)10-(50)x-(4x)10+(4x)x]x
=[(50)10-(50)x+(-4x)10-(-4x)x]x
=(50-4x)(10-x)x
2007-01-18 21:33:44 補充：
=(50-4x)(10-x)x其實可以仲簡單D ga=2x(2x-25)(x-10)鐘唔鐘意見仁見智
(500-50x-40x+4x2)x
=[(50)10-(50)x-(4x)10+(4x)x]x
=[(50)10-(50)x+(-4x)10-(-4x)x]x
=(50-4x)(10-x)x
2007-01-18 21:33:44 補充：
=(50-4x)(10-x)x其實可以仲簡單D ga=2x(2x-25)(x-10)鐘唔鐘意見仁見智
參考: me
2007-01-19 5:31 am
(500-50x-40x+4x^2)*x
＝500x-50x^2-40x^2+4x^3
＝500x-90x^2+4x^3
＝500x-50x^2-40x^2+4x^3
＝500x-90x^2+4x^3
參考: my knowledge
收錄日期: 2021-04-12 21:33:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070118000051KK04267