代數題唔識計......請幫下我.......top urgent !!!!!
回答 (5)
2007-01-17 6:10 am
✔ 最佳答案
設全場共有x隻家禽因為鴨子佔60%, 雞則佔40%, 而鴨比雞多4隻:
60%x=40%x+4
0.6x=0.4x+4
0.6x-0.4x=4
0.2x=4
x=4/0.2
x=20
∴全場共有20隻家禽
2007-01-16 22:11:56 補充：
順便驗證埋：鴨有20*60%=20*0.6=12隻雞有20*40%=20*0.4=8隻12-8=4(隻)即係鴨比雞多4隻
參考: me
2007-01-17 8:35 am
設全場共有x隻家禽.
60%x = 40%x + 4
0.6x = 0.4x + 4
0.2x = 4
x = 20
因此全場共有20隻家禽.
鴨子數目 = 20(0.6) = 12隻
雞的數目 = 20(0.4) = 8隻
60%x = 40%x + 4
0.6x = 0.4x + 4
0.2x = 4
x = 20
因此全場共有20隻家禽.
鴨子數目 = 20(0.6) = 12隻
雞的數目 = 20(0.4) = 8隻
2007-01-17 6:19 am
let the number of fowls in the farm be x
then 60%x are ducks, 40%x are chickens
0.6x-0.4x=4
0.2x =4
x =20
so, there are 20 fowls in the farm.
then 60%x are ducks, 40%x are chickens
0.6x-0.4x=4
0.2x =4
x =20
so, there are 20 fowls in the farm.
參考: my brain
2007-01-17 6:16 am
60+4+X=100
X=100-60-4
X=36
X=100-60-4
X=36
收錄日期: 2021-04-12 21:32:56
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https://hk.answers.yahoo.com/question/index?qid=20070116000051KK04794