(1)小明以25%的折扣百分率買入兩塊相同的網球拍，省了$500，找出每塊網球拍的售價。
(2)一群中學生以$3000投得一個年宵攤位。他們以$12000向玩具商買入1000個公仔，準備在年宵攤位中以每個$20的價錢出售。(a)他們的創業成本是多少?(b)若全部公仔出售，問盈利百分率是多少?(c)到左深夜12時，還有120個公仔未售出。問此時的盈利或虧蝕百分率是多少?(d)若120個公仔最後以每個$10的價錢全部售出，問整體的盈利或虧蝕百分率是多少? 我打得好辛苦架，請講出答案及原因。
(數學高手)中一數學題。
2007-01-16 1:48 am
回答 (3)
2007-01-16 2:14 am
2y x 25% = 500
2y =500/25%
2y =2000
y =2000/2
y =1000
2y =500/25%
2y =2000
y =2000/2
y =1000
2007-01-16 2:07 am
(1) Let say Y=sale price of each tennis racket
Y x 25% =500 / 2
0.25Y=250
Y=$1000
(2a) 3000 + 12000 = $15,000
(2b) [(20000-12000-3000)/ 15000] x 100%=33.33% profit
(2c) [((880x20)-3000-12000))/15000] x 100%=17.33% profit
(2d) [((880x20)+(120x10)-15000)/15000] x 100% = 25.33% profit
Y x 25% =500 / 2
0.25Y=250
Y=$1000
(2a) 3000 + 12000 = $15,000
(2b) [(20000-12000-3000)/ 15000] x 100%=33.33% profit
(2c) [((880x20)-3000-12000))/15000] x 100%=17.33% profit
(2d) [((880x20)+(120x10)-15000)/15000] x 100% = 25.33% profit
2007-01-16 1:57 am
( 1 ) 設 $y 是每塊網球拍的售價
2y x 25% = 500
2y =500/25%
2y =2000
y =2000/2
y =1000
2y x 25% = 500
2y =500/25%
2y =2000
y =2000/2
y =1000
收錄日期: 2021-04-23 16:33:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070115000051KK02971