✔ 最佳答案
please help to solve the following problems:
1. a hanging magnet of weight 0.5N is attracted by anothermsgnry hotizontally so that the string make an angle of 15 degree to the vertical.
a. what is the tension T in the string?
Let the tension be T.
The vertical component of tension
= Tcos15°
As the magnet is static (no acceleration), so net force = 0
So vertical component of tension = weight of magnet
Tcos15° = 0.5
T = 0.5176 N
So the tension is 0.5176N.
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b. What is the force between the magnets?
Horizontal component of tension
= Tsin15°
=(0.5176)sin15° 【From (a)】
= 0.1340 N
As the magnet is static (no acceleration), so net force = 0
So horizontal component of tension = magnet attraction force
The magnet attraction force = 0.1340N