計算以下題目
√(9!) + ∣(3+4)(12x2-33)∣
= ?
開方, 絕對值,?
2007-01-14 8:38 pm
回答 (3)
2007-01-14 9:11 pm
√(9!) +∣ (3+4)(12x2-33)∣
= √((9x8x7x6x5x4x3x2x1)+∣7x(-9)∣
=√( 362880 +∣-63∣
=√(362880+63
=602+63
=665
= √((9x8x7x6x5x4x3x2x1)+∣7x(-9)∣
=√( 362880 +∣-63∣
=√(362880+63
=602+63
=665
2007-01-14 9:01 pm
√(9!) +∣(3+4)(12x2-33)∣
=√362880+∣-63∣
=665
=√362880+∣-63∣
=665
2007-01-14 8:46 pm
72*sqrt(70)+63
=602.395+63
=665.395
=665 (to 3 significant figures)
=602.395+63
=665.395
=665 (to 3 significant figures)
收錄日期: 2021-04-12 20:10:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070114000051KK01664