✔ 最佳答案
9.
(a) 設r cm為扇形的半徑
πr^2 (80°/360°) = 162π
r^2 = 729
r = 27
∴ 扇形的半徑是27cm
(b) 扇形的周界
= 2πr (80°/360°) + 2r
= π(27) (1/9) + 2(27)
= (3π + 54)cm
10.
(a) 設y = ax^2 + bx, a和b為非零常數
當x = 3, y = 3
9a + 3b = 3
3a + b = 1......(i)
當x = 4, y = 12
16a + 4b = 12
4a + b = 3......(ii)
(ii) - (i) : a = 2
Sub. a = 2 into (i)
3(2) + b = 1
b = -5
∴ y = 2x^2 - 5x
(b) ∵ y < 42
∴ 2x^2 - 5x < 42
2x^2 - 5x - 42 < 0
(2x + 7)(x - 6) < 0
∴ -7/2 < x < 6
因x是整數,
x 所有可取值為 -3, -2, -1, 0, 1, 2, 3, 4及5
12.
(a)(i) ∵ CD = CE
∴ ∠CED = ∠CDE = 36°
所以∠AEF = ∠CED = 36°
(ii) ∠ACB = ∠CDE + ∠CED = 36°+ 36°= 72°
∵ AB = AC
∴ ∠ABC = ∠ACB = 72°
∵ ∠BAC = 180°- 72°- 72°
∴ ∠BAC = 36°
(b)(i) 在ΔAEF
∠BFE = 36°+ 36°= 72° (Δ的外角)
∵ ∠AEF = ∠EAF = 36°
∴ AF = EF (底角相等)
∵ AF = FB
∴ EF = FB
∠FEB + ∠FBE + 72° = 180° (Δ的內角和)
∠FEB = ∠FBE = (180°- 72°)/2 = 54° (等腰Δ底角)
∠AEB = 54°+ 36°= 90°
∴∠AEB 是一個直角
(ii) cos36°= 10/AB
AB = 10/cos36°
ΔABC的面積 = 1/2 (AB)(AC)sin36°
= 1/2 (10/cos36°)^2 sin36°
= 44.9cm^2
13.
(a)(i) 設E的座標為(x, y)
x = (2 + 8)/2 = 5
y = (9 + 1)/2 = 5
∴E的座標是(5, 5)
(ii) ∵ ABCD是一個菱形
∴ BD垂直於AC
AC的斜率 = (9 - 1)/(2 - 8) = -4/3
BD的斜率 = -1/(-4/3) = 3/4
BD的方程是
y - 5 = 3/4 (x - 5)
3x - 4y + 5 = 0......(1)
(b)(i) BC的斜率
= AD的斜率
= -1/7
BC的方程是
y - 1 = -1/7 (x - 8)
x + 7y - 15 = 0......(2)
(ii) 設B的座標為(h, k)
代 (h, k) 入 (1) 和 (2)
3h - 4k + 5 = 0......(3)
h + 7k - 15 = 0......(4)
(3) - 3x(4) :
-25k + 50 = 0
k = 2
代 k = 2 入 (4) :
h + 7(2) - 15 = 0
h = 1
∴ B的座標是(1, 2)
AB = √[(2 - 1)^2 + (9 - 2)^2]
= √50
= 5√2
你另外的題目
設分別買了橙子和蘋果a個和b個
a + b = 20......(i)
2a + 3b = 46......(ii)
3 x (i) - (ii):
(3a + 3b) - (2a + 3b) = 60 - 46
a = 14
∴ 購買橙子的數目是14個
呼~~終於完成了
2007-01-12 15:55:10 補充:
計錯了(b) 扇形的周界= 2πr (80°/360°) 2r= π(27) (4/9) 2(27)= (12π 54)cm