04年數學會考題目 急急急

2007-01-12 10:08 pm
尼個網址入面有4條會考題,好難解到,請好心人幫幫忙!thx~
http://hk.pg.photos.yahoo.com/ph/wing13com2002/album?.dir=5957scd&.src=ph&store=&prodid=&.done=http%3a//hk.pg.photos.yahoo.com/ph/wing13com2002/my_photos

除此之外,另一題:一個橙子及一個蘋果的價錢分別為$2及$3。現在花費了$46購買若干個橙子和蘋果。若所購買的橙子和蘋果的總數為20,求所購買橙子的數目。(答案14個)

註:所有題目要列全式,thanks!

回答 (4)

2007-01-12 11:52 pm
✔ 最佳答案
9.
(a) 設r cm為扇形的半徑
πr^2 (80°/360°) = 162π
       r^2 = 729
        r = 27
∴ 扇形的半徑是27cm
(b) 扇形的周界
= 2πr (80°/360°) + 2r
= π(27) (1/9) + 2(27)
= (3π + 54)cm

10.
(a) 設y = ax^2 + bx, a和b為非零常數
當x = 3, y = 3
  9a + 3b = 3
   3a + b = 1......(i)
當x = 4, y = 12
  16a + 4b = 12
   4a + b = 3......(ii)
(ii) - (i) : a = 2
Sub. a = 2 into (i)
   3(2) + b = 1
      b = -5
∴ y = 2x^2 - 5x
(b) ∵ y < 42
∴ 2x^2 - 5x < 42
2x^2 - 5x - 42 < 0
(2x + 7)(x - 6) < 0
  ∴ -7/2 < x < 6
因x是整數,
x 所有可取值為 -3, -2, -1, 0, 1, 2, 3, 4及5

12.
(a)(i)    ∵ CD = CE
   ∴ ∠CED = ∠CDE = 36°
  所以∠AEF = ∠CED = 36°
 (ii) ∠ACB = ∠CDE + ∠CED = 36°+ 36°= 72°
    ∵   AB = AC
    ∴ ∠ABC = ∠ACB = 72°
    ∵ ∠BAC = 180°- 72°- 72°
    ∴ ∠BAC = 36°
(b)(i) 在ΔAEF
   ∠BFE = 36°+ 36°= 72°         (Δ的外角)
  ∵ ∠AEF = ∠EAF = 36°
  ∴ AF = EF                 (底角相等)
  ∵ AF = FB
  ∴ EF = FB
  ∠FEB + ∠FBE + 72° = 180°        (Δ的內角和)
  ∠FEB = ∠FBE = (180°- 72°)/2 = 54°    (等腰Δ底角)
  ∠AEB = 54°+ 36°= 90°
  ∴∠AEB 是一個直角
 (ii) cos36°= 10/AB
     AB = 10/cos36°
  ΔABC的面積 = 1/2 (AB)(AC)sin36°
         = 1/2 (10/cos36°)^2 sin36°
         = 44.9cm^2

13.
(a)(i) 設E的座標為(x, y)
   x = (2 + 8)/2 = 5
   y = (9 + 1)/2 = 5
  ∴E的座標是(5, 5)
 (ii) ∵ ABCD是一個菱形
   ∴ BD垂直於AC
  AC的斜率 = (9 - 1)/(2 - 8) = -4/3
  BD的斜率 = -1/(-4/3) = 3/4
    BD的方程是
      y - 5 = 3/4 (x - 5)
   3x - 4y + 5 = 0......(1)
(b)(i) BC的斜率
  = AD的斜率
  = -1/7
   BC的方程是
     y - 1 = -1/7 (x - 8)
  x + 7y - 15 = 0......(2)
 (ii) 設B的座標為(h, k)
  代 (h, k) 入 (1) 和 (2)
   3h - 4k + 5 = 0......(3)
   h + 7k - 15 = 0......(4)
  (3) - 3x(4) :
     -25k + 50 = 0
        k = 2
  代 k = 2 入 (4) :
    h + 7(2) - 15 = 0
         h = 1
   ∴ B的座標是(1, 2)
   AB = √[(2 - 1)^2 + (9 - 2)^2]
     = √50
     = 5√2

你另外的題目
設分別買了橙子和蘋果a個和b個
 a + b = 20......(i)
2a + 3b = 46......(ii)

3 x (i) - (ii):
(3a + 3b) - (2a + 3b) = 60 - 46
         a = 14

∴ 購買橙子的數目是14個

呼~~終於完成了

2007-01-12 15:55:10 補充:
計錯了(b) 扇形的周界= 2πr (80°/360°) 2r= π(27) (4/9) 2(27)= (12π 54)cm
2007-01-13 4:05 am
Let the number of orange bought be x,
then the number of apple bought wil be (20 - x)

By given, we have 2x + 3(20 - x) = 46
Simplify gives x = 14
2007-01-12 11:26 pm
let 橙 be x 蘋果 be y

2x+3y=46---------a
x+y=20-------b
a-3b
x=14 ,y=6
橙有14個
2007-01-12 10:38 pm
設買了橙x個,蘋果y個
因為共花了$46,所以3x+2y=46...(1號式)
因為總數為20,所以x+y=20
則係y=20-x...(2號式)
將2號式代入1號式
3x+2(20-x)=46
3x+40-2x=46
x=6
y=14


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