1. factorize 3a{2}-a+9ab-3b {2}=2次方
2. factorize 3t{2}-2t-1 {2}=2次方
請解答maths
2007-01-11 1:22 am
回答 (3)
2007-01-11 1:29 am
✔ 最佳答案
3a{2}-a+9ab-3b =a(3a-1)+b(3a-1)
=(3a-1)(a+b)
3t{2}-2t-1
=(t-1)(3t+1)
1t -1
3t +1
------------
3t{2} -3t+1t=-2t -1
2007-01-10 17:31:37 補充：
第一題係抽3b....打錯左答案係(3a-1)(a 3b)
2007-01-10 17:32:05 補充：
(3a-1)(a 3b)
參考: 自己
2007-01-11 1:32 am
1.3a{2}-a+9ab-3b
= a(3a-1)+3b(3a-1)
= (a+3b)(3a-1)//
2.3t{2}-2t-1
= (3t-1)(t+1) 3t -1
So, t = 1/3 or -1 t 1
2007-01-10 17:34:36 補充：
最尾係 t = 1/3 or t = -1
= a(3a-1)+3b(3a-1)
= (a+3b)(3a-1)//
2.3t{2}-2t-1
= (3t-1)(t+1) 3t -1
So, t = 1/3 or -1 t 1
2007-01-10 17:34:36 補充：
最尾係 t = 1/3 or t = -1
參考: 自己
2007-01-11 1:29 am
3a^2-a+9ab-3b
=a(3a-1)+3b(3a-1)
=(a+3b)(3a-1)
3t^2-2t-1
=(3t+1)(t-1)
^2=2次方
=a(3a-1)+3b(3a-1)
=(a+3b)(3a-1)
3t^2-2t-1
=(3t+1)(t-1)
^2=2次方
收錄日期: 2021-04-12 22:00:30
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