問題出沒注意!!! Chem 3

2007-01-09 11:42 pm
Please arrange the following acids in ascending order according to their corrodibility:

i. Dilute hydrochloric acid (0.1 M)
ii. Dilute sulphuric acid (0.1 M)
iii. Dilute nitric acid (0.1 M)
iv. Conc. hydrochloric acid (11 M)
v. Conc. sulphuric acid (16 M)
vi. Conc. nitric acid (18 M)

Thx for answering and helping~

回答 (1)

2007-01-10 11:04 pm
✔ 最佳答案
First of all, let's have a view of what other properties (besides acidic property) do those acids have in addition:
Conc. H2SO4: Dehydrating (脫水), Oxidizing (氧化) and Involatility (非揮發性)
Conc. HNO3: Oxidizing (even stronger than conc. H2SO4)
Dil. HNO3: Oxidizing (weaker than conc. H2SO4)
And for the remaining acids (Conc. HCl, dil. H2SO4 and dil. HCl), they are for sure be not as corrosive as the 3 acids above since they only have acidity as their properties.
Therefore, for these 3 acids, only acidity has to be counted and hence the corrosive power is:
Dil. HCl < Dil. H2SO4 < Conc. HCl (which is the order of concentration of H+ ions in them.)
And for the other more corrosive acids, conc. H2SO4 is for sure to be the most corrosive owing to more properties of it. Say if spilt on human skin, the skin tissues will be oxidized and dehydrated, leaving a black residue (which is mainly composed of carbon).
Then for oxidizing power, conc. HNO3 > dil. HNO3.
So the whole ascending order of corrodibility is:
conc. H2SO4 > conc. HNO3 > dil. HNO3 > conc. HCl > dil. H2SO4 > dil. HCl
參考: My chemical knowledge


收錄日期: 2021-04-30 13:35:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070109000051KK01821

檢視 Wayback Machine 備份