A F. 2 Maths question - Factorization by using identities
a^2-8a+16-y^2
Please show your working steps clearly and explain your answer in details.
A F. 2 Maths question - Factorization by using identities
2007-01-09 10:22 pm
回答 (3)
2007-01-09 10:26 pm
✔ 最佳答案
a^2 - 8a + 16 - y^2= a^2 - 2(a)(4) + 4^2 - y^2
= (a - 4)^2 - y^2 ∵(a - b)^2 = a^2 - 2ab + b^2
= (a - 4 + y)(a - 4 - y) ∵a^2 - b^2 = (a + b)(a - b)
2007-01-10 12:50 am
a^2-8a+16-y^2
=(a-4)^2-y^2
=[(a-4)+y][(a-4)-y]
=(a-4+y)(a-4-y)
=(a-4)^2-y^2
=[(a-4)+y][(a-4)-y]
=(a-4+y)(a-4-y)
參考: 計的...
2007-01-09 11:58 pm
a^2 - 8a + 16 - y^2
= a^2 - 2(a)(4) + 4^2 - y^2
= (a - 4)^2 - y^2 ∵(a - b)^2 = a^2 - 2ab + b^2
= (a - 4 + y)(a - 4 - y) ∵a^2 - b^2 = (a + b)(a - b)
= a^2 - 2(a)(4) + 4^2 - y^2
= (a - 4)^2 - y^2 ∵(a - b)^2 = a^2 - 2ab + b^2
= (a - 4 + y)(a - 4 - y) ∵a^2 - b^2 = (a + b)(a - b)
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