Identities
回答 (2)
2007-01-09 8:06 am
✔ 最佳答案
a^2+b^2can have the following 2 presentations
1. It is not an algebraic identity.
2.
a^2+b^2
= a^2+2ab+b^2-2ab
= (a+b)^2 - 2ab
參考: me
2007-01-10 2:29 am
a² + b² = (a + b)² - 2ab
附註：
a² - b² = (a + b)(a - b)
a³ + b³ = (a + b)(a² - ab + b²)
a³ - b³ = (a - b)(a² + ab + b²)
n-1n-2n-2n-1
aⁿ - bⁿ = (a - b)(a+ ab + ... + ab+ b), for all n is odd
附註：
a² - b² = (a + b)(a - b)
a³ + b³ = (a + b)(a² - ab + b²)
a³ - b³ = (a - b)(a² + ab + b²)
n-1n-2n-2n-1
aⁿ - bⁿ = (a - b)(a+ ab + ... + ab+ b), for all n is odd
收錄日期: 2021-04-12 22:50:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070108000051KK05205