Solve the follwing literal equation for z.
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3)計到正確答案
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2007-01-08 6:58 am
回答 (4)
2007-01-08 7:03 am
✔ 最佳答案
2z/a - C = z/3a + 7移項：
2z/a = z/3a + 7 + C
移項：
2z/a - z/3a = 7 + C
整理：
(2 - 1/3)z/a = 7 + C
整理：
(5/3)z/a = 7 + C
左右乘3/5：
z/a = 3(7 + C)/5
左右乘a：
z = 3a(7 + C)/5
參考: me, 好詳細
2007-01-18 5:42 pm
2z/a - c = z/3a + 7
同分母: (2z-ac)/a = (z+21a)/3a
交差相乘: (2z-ac) x 3a = (z+21a) x a
做約簡: 3(2z-ac) = a(z+21a)
6z-3ac = az + 21a2(a二次方)
6z-az = 21a2 - 3ac
z(6-a) = 3a( 7a-c)
z = [3a(7a-c)]/(6-a)
同分母: (2z-ac)/a = (z+21a)/3a
交差相乘: (2z-ac) x 3a = (z+21a) x a
做約簡: 3(2z-ac) = a(z+21a)
6z-3ac = az + 21a2(a二次方)
6z-az = 21a2 - 3ac
z(6-a) = 3a( 7a-c)
z = [3a(7a-c)]/(6-a)
2007-01-13 3:18 am
2z/a - c = z/3a + 7 ＜－題目
(2z/a - c) = (z/3a + 7)
6z - 3ac = z + 21a
6z - 3ac = z + 21a
5z - 3ac = 21a
5z = 21a
5z = 3a(7 + c)
z = 3a(7 + c)/5 ＜－ 案答
(2z/a - c) = (z/3a + 7)
6z - 3ac = z + 21a
6z - 3ac = z + 21a
5z - 3ac = 21a
5z = 21a
5z = 3a(7 + c)
z = 3a(7 + c)/5 ＜－ 案答
2007-01-10 8:24 am
2z/a - c = z/3a + 7
3a x (2z/a - c) = 3a x (z/3a + 7) [兩邊乘3a，個人認為分數冇咁好做]
6z - 3ac = z + 21a
6z - 3ac - z = z + 21a - z [答題時這步可省略]
5z - 3ac = 21a [答題時這步可省略]
5z - 3ac + 3ac = 21a + 3ac [答題時這步可省略]
5z = 3a(7 + c) [最好當然係factorize左佢啦，唔做都可以，因題目冇要求]
z = 3a(7 + c)/5
3a x (2z/a - c) = 3a x (z/3a + 7) [兩邊乘3a，個人認為分數冇咁好做]
6z - 3ac = z + 21a
6z - 3ac - z = z + 21a - z [答題時這步可省略]
5z - 3ac = 21a [答題時這步可省略]
5z - 3ac + 3ac = 21a + 3ac [答題時這步可省略]
5z = 3a(7 + c) [最好當然係factorize左佢啦，唔做都可以，因題目冇要求]
z = 3a(7 + c)/5
收錄日期: 2021-04-12 21:25:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070107000051KK05605