Elimination
How to solve?
x/5+y/4=1
5-y =x-1
F.2 Maths----- Linear Equations in Two Unknown
2007-01-07 10:27 pm
回答 (2)
2007-01-07 10:52 pm
✔ 最佳答案
x/5 + y/4 =14x + 5y = 20 [兩邊各乘 20]
5 - y = x - 1
x = 6 - y
Therefore, 4(6-y) + 5y = 20
y = -4
x = 6 - (-4) = 10
2007-01-08 5:36 am
5-y = x-1
y = 6-x
x/5+y/4=1
x/5+(6-x)/4=1
20x/5+20(6-x)/4=20
4x+30-5x=20
x=10
y=-4
y = 6-x
x/5+y/4=1
x/5+(6-x)/4=1
20x/5+20(6-x)/4=20
4x+30-5x=20
x=10
y=-4
收錄日期: 2021-04-13 13:31:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070107000051KK02289