一男童量得一長方形的長和闊分別為3.9cm和4.4cm.若該長方形的真實尺寸是
4cm*4.5cm,求下列各項的百分誤差
(a)闊度
(b)長度
(c)長方形的面積
(2/5)^-1
為什麼是5/2,而不是2/5
百分誤差和指數help
2007-01-07 7:39 pm
回答 (2)
2007-01-07 7:57 pm
✔ 最佳答案
(a)闊度百分誤差
=(0.1/4.5) x 100%
=2.22%
(b)長度
百分誤差
=(0.1/4) x 100%
=2.5%
(c)長方形的面積
= ((4x4.5-3.9x4.4) / (4x4.5)) x 100%
= (0.84 / 18) x 100%
=4.67%
(2/5)^ -1
=1/ (2/5)
=5/2
2007-01-07 8:03 pm
a (4-3.9)/4 X100% = 2.5%
b (4.5-4.4)/4.5 X100%= 2.22222%
c (18-17.16)/18 X100%= 4.6666666%
(2/5)^-1
=2^-1/5^-1
=5/2 根據指數定律a^-1 =1/a
2007-01-07 12:04:51 補充：
我覺得條問題長闊互相調轉左有咩理由長短過闊???
b (4.5-4.4)/4.5 X100%= 2.22222%
c (18-17.16)/18 X100%= 4.6666666%
(2/5)^-1
=2^-1/5^-1
=5/2 根據指數定律a^-1 =1/a
2007-01-07 12:04:51 補充：
我覺得條問題長闊互相調轉左有咩理由長短過闊???
收錄日期: 2021-04-12 22:01:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070107000051KK01326