Let f(x) = x^2 + 10x +24
(a) Factoeize f(x)
(b) Hence or otherwise,factorize f( p^2 - 5p )
Let f(x) = x^2 + 10x +24
2007-01-07 12:42 am
回答 (4)
2007-01-07 12:48 am
✔ 最佳答案
(a)f(x)
= x^2 + 10x +24
=(X+4)(X+6)
(b)
f( p^2 - 5p )
=( p^2 - 5p )^2+10( p^2 - 5p )+24
=( p^2 - 5p +4)( p^2 - 5p +6)
=(p-1)(p-4)(p-2)(p-3)
=(p-1)(p-2)(p-3)(p-4)
2007-01-07 2:06 am
(a) (x+4)(x+6)
(b) (p-1)(p-4)(p-2)(p-3)
(b) (p-1)(p-4)(p-2)(p-3)
2007-01-07 12:49 am
(a) (x+4)(x+6)
(b) f(p^2-5p) = (p^2-5p+4)(p^2-5p+6)
= (p-1)(p-4)(p-2)(p-3)
(b) f(p^2-5p) = (p^2-5p+4)(p^2-5p+6)
= (p-1)(p-4)(p-2)(p-3)
2007-01-07 12:48 am
a)f(x)=x^2+10x+24
=(x+4)(x+6),x=-6or-4
b)f(p^2-5p)=(p^2-5p)^2+10(p^2-5p)+24
=(p^2-5p+4)(p^2-5p+6)
=(p-4)(p-1)(p-2)(p-3)
=(x+4)(x+6),x=-6or-4
b)f(p^2-5p)=(p^2-5p)^2+10(p^2-5p)+24
=(p^2-5p+4)(p^2-5p+6)
=(p-4)(p-1)(p-2)(p-3)
收錄日期: 2021-04-23 19:53:16
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