✔ 最佳答案
第 7 至 10 題,其實每條問都是相似,有個 sin 和 cos 的實真你要先知道:
For all real θ,
-1 ≦ sinθ ≦ 1
-1 ≦ cosθ ≦ 1
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find the max. and min. value of y for all value of x
7〕 y = - ( 1/4 ) cos ( x/2 )
ans : 1/4, - 1/4
-1 ≦ cos (x/2) ≦ 1
1/4 ≧ (-1/4)cos(x/2) ≧ -1/4
1/4 ≧ y ≧ -1/4
So the minimum value of y is -1/4, the maximum value is 1/4
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8〕y = 2 cos ^2 ( π+ x/2 )
ans : 2 , 0
-1 ≦ cos (π + x/2) ≦ 1
0 ≦ cos^2(π + x/2) ≦ 1^2
0 ≦ cos^2(π + x/2) ≦ 1
0 ≦ 2 cos^2(π + x/2) ≦ 2
0 ≦ y ≦ 2
So the minimum value of y is 0, the maximum value is 2
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9〕y= 4 sin ^2 ( x/3 ) - 3
ans : 1 , - 3
-1 ≦ sin (x/3) ≦ 1
0 ≦ sin^2(x/3) ≦ 1^2
0 ≦ sin^2(x/3) ≦ 1
0 ≦ 4 sin^2(x/3) ≦ 4
0-3 ≦ sin^2(x/3)-3 ≦ 4-3
-3 ≦ sin^2(x/3)-3 ≦ 1
-3 ≦ y ≦ 1
So the minimum value of y is -3, the maximum value is 1
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10〕y = 1 - ( 1/2 ) sin ( 2x + π/3 )
ans : 3/2 , 1/2
-1 ≦ sin (2x + π/3) ≦ 1
1/2 ≧ -(1/2) sin (2x + π/3) ≧ -1/2
1/2 + 1 ≧ -(1/2) sin (2x + π/3) + 1 ≧ -1/2 + 1
3/2 ≧ 1 - (1/2) sin (2x + π/3) ≧ 1/2
3/2 ≧ y ≧ 1/2
So the minimum value of y is 1/2, the maximum value is 3/2
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11〕if sin A and cos A both increase as A increase, in which quadrant does A lie ?
quad. 4
Recall the range change of sin and cos in the 4 quadrant:
sinθ from 0 to 1 for θ = 0 to π/2 [increasing]
sinθ from 1 to 0 for θ = π/2 to π [decreasing]
sinθ from 0 to -1 for θ = π to 3π/2 [decreasing]
sinθ from -1 to 0 for θ = 3π/2 to 2π [increasing]
cosθ from 1 to 0 for θ = 0 to π/2 [decreasing]
cosθ from 0 to -1 for θ = π/2 to π [decreasing]
cosθ from -1 to 0 for θ = π to 3π/2 [increasing]
cosθ from 0 to 1 for θ = 3π/2 to 2π [increasing]
So when sinθ and cosθ both increasing, the quadrant is 4.
2007-01-06 01:02:20 補充:
小小補充:第 7-10 題,因為題目只是問 y 的最小及最大值,其實與角度無關,所以只要考慮 sinθ 及 cosθ 的範圍便可。