問題:(3x-1)^2=(8x+2)^2
(8x+2)^2-(3x-1)^2=0
(11X+1)(5x+3)=0
x=-1/11 or x=-3/5
二次方程問題2
2007-01-06 7:59 am
回答 (4)
2007-01-06 8:10 am
✔ 最佳答案
(3x-1)^2=(8x+2)^2兩邊開方
(3x-1)=(8x+2) 或 (3x-1)=-(8x+2)
若
(3x-1)=(8x+2)
-5x=3
x=-3/5
若
(3x-1)=-(8x+2)
11x=-1
x=-1/11
或者用你個方法
(8x+2)^2-(3x-1)^2=0
(11X+1)(5x+3)=0
x=-1/11 or x=-3/5
所以你0岩而上面個個人錯
2007-01-06 8:27 am
(3x-1)^2=(8x+2)^2
9x^2-2(3x)+1=64x^2+32x+4
55x^2+38x+3=0
x=-(3/5) or -(1/11)
岩
9x^2-2(3x)+1=64x^2+32x+4
55x^2+38x+3=0
x=-(3/5) or -(1/11)
岩
參考: MESELF
2007-01-06 8:06 am
( 3x - 1 )^2 = ( 8x + 2 )^2
3x - 1 = 8x + 2 ... 左右方同時 √ ( 開方 )
8x - 3x = -1 - 2
5x = -3
x = - 3/5 or - 0.6
收錄日期: 2021-04-13 15:22:00
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