二次方程問題

(2x+1)(x-2) = (x-2)
(2x+1)(x-2)-(x-2)= 0
(x-2)(2x+1-1) = 0
2x(x-2) = 0

2x = 0 or x-2 = 0
x= 0 x = 2

你無錯呀~~~~

(2x+1)(x-2) = (x-2)
(2x+1)(x-2)-(x-2)= 0
(x-2)(2x+1-1) = 0
2x(x-2) = 0

2x = 0 or x-2 = 0
x= 0 x = 2

(2x+1)(x-2)-(x-2) =0（先X除, 后加減 你都唔記得，等一個step都錯la)

試下咁:
(2x+1)(x-2) = x-2
2x(二次方)+x-4x-2 = x-2
2x(二次方)-3x-2 = x-2
2x(二次方)-3x = x-2+2
2x(二次方) = x+3x
2x(二次方) = 4x
x(二次方) = 4x/2
x(二次方) = 2x
x‧x = 2x (相方各取消１個ｘ）
x = 2

(2x+1)(x-2)=x-2
2x^2-4x+x-2=x-2
2x^2-4x=0
x=0 or x=2

你冇錯~~

Nothing wrong... just ur teacher wrong

(2x+1)(x-2)=x-2
(2x+1)=(x-2)/(x-2)
2X+1=1
2x=0
x=0