2條數學題[吾該哂]

Q1.

g = a + b / a - b

ga - gb = a + b

ga - a = gb + b

a (g - 1) = b (g + 1)

a = b (g + 1) / (g - 1)


Q2.

3 / m - 2 / (m + 1)

= [ 3 ( m + 1) - 2m ] / m (m + 1)

= (3m + 3 - 2m) / m (m + 1)

= (m + 3 ) / m (m + 1)

有d括號係方便你睇，寫ｏ既時候可以唔駛要

g=a+b/a-b
g(a-b)=a+b
g(a)-g(b)=a+b
g(a)-a=g(b)+b
a(g-1)=b(g+1)
a=b(g+1)/(g-1)


3/m-2/m+1
=3(m+1)-2(m)/m(m+1)
=3m+3-2m/m(m+1)
=m+3/m(m+1)

1) g = (a+b)/(a-b)
g(a-b) = (a+b)
ga-gb = a+b
a(g-1) = b(g+1)
a = b(g+1)/(g-1)

2) 3/m - 2/m + 1
= 1/m + 1

g= a+b / a-b
g(a-b) = a+b
ga - gb = a+b
ga - a = b + gb
a(g-1) = b(1+g)

a = b(g+1)/(g-1)



3/m - 2/m+1
=3(m+1)/[m(m+1)] - 2m/[m(m+1)]....將第一項上面同下面都乘m+1, 第二項上面同下面都乘m
=(3m + 3 - 2m)/[m(m+1)] ....通分母
=(m+3)/[m(m+1)]


.....m+3
= -----------
...m(m+1)

g = (a+b)/(a-b)
g*(a-b)=(a+b)
ga-gb=a-b
ga-a=gb+b
a(g-1)=b(g+1)
a=b(g+1)/(g-1)




3/m - 2/(m+1)
=[3(m+1) - 2m] / [ m(m+1)]
=(m+3) / [ m(m+1) ]