a+b
g= -----
a-b
將a轉做主項,,答案是 ..?列出步驟 ..吾該哂"*`
3 2
-- 減 -----
m m+1
請化簡 `..列出步驟 ...*''吾該哂 =]
2條數學題[吾該哂]
2007-01-06 12:06 am
回答 (5)
2007-01-06 12:25 am
✔ 最佳答案
Q1. g = a + b / a - b
ga - gb = a + b
ga - a = gb + b
a (g - 1) = b (g + 1)
a = b (g + 1) / (g - 1)
Q2.
3 / m - 2 / (m + 1)
= [ 3 ( m + 1) - 2m ] / m (m + 1)
= (3m + 3 - 2m) / m (m + 1)
= (m + 3 ) / m (m + 1)
有d括號係方便你睇，寫ｏ既時候可以唔駛要
參考: 自己
2007-01-08 12:12 pm
g=a+b/a-b
g(a-b)=a+b
g(a)-g(b)=a+b
g(a)-a=g(b)+b
a(g-1)=b(g+1)
a=b(g+1)/(g-1)
3/m-2/m+1
=3(m+1)-2(m)/m(m+1)
=3m+3-2m/m(m+1)
=m+3/m(m+1)
g(a-b)=a+b
g(a)-g(b)=a+b
g(a)-a=g(b)+b
a(g-1)=b(g+1)
a=b(g+1)/(g-1)
3/m-2/m+1
=3(m+1)-2(m)/m(m+1)
=3m+3-2m/m(m+1)
=m+3/m(m+1)
參考: 自己
2007-01-06 12:28 am
1) g = (a+b)/(a-b)
g(a-b) = (a+b)
ga-gb = a+b
a(g-1) = b(g+1)
a = b(g+1)/(g-1)
2) 3/m - 2/m + 1
= 1/m + 1
g(a-b) = (a+b)
ga-gb = a+b
a(g-1) = b(g+1)
a = b(g+1)/(g-1)
2) 3/m - 2/m + 1
= 1/m + 1
2007-01-06 12:25 am
g= a+b / a-b
g(a-b) = a+b
ga - gb = a+b
ga - a = b + gb
a(g-1) = b(1+g)
a = b(g+1)/(g-1)
3/m - 2/m+1
=3(m+1)/[m(m+1)] - 2m/[m(m+1)]....將第一項上面同下面都乘m+1, 第二項上面同下面都乘m
=(3m + 3 - 2m)/[m(m+1)] ....通分母
=(m+3)/[m(m+1)]
.....m+3
= -----------
...m(m+1)
g(a-b) = a+b
ga - gb = a+b
ga - a = b + gb
a(g-1) = b(1+g)
a = b(g+1)/(g-1)
3/m - 2/m+1
=3(m+1)/[m(m+1)] - 2m/[m(m+1)]....將第一項上面同下面都乘m+1, 第二項上面同下面都乘m
=(3m + 3 - 2m)/[m(m+1)] ....通分母
=(m+3)/[m(m+1)]
.....m+3
= -----------
...m(m+1)
2007-01-06 12:22 am
g = (a+b)/(a-b)
g*(a-b)=(a+b)
ga-gb=a-b
ga-a=gb+b
a(g-1)=b(g+1)
a=b(g+1)/(g-1)
3/m - 2/(m+1)
=[3(m+1) - 2m] / [ m(m+1)]
=(m+3) / [ m(m+1) ]
g*(a-b)=(a+b)
ga-gb=a-b
ga-a=gb+b
a(g-1)=b(g+1)
a=b(g+1)/(g-1)
3/m - 2/(m+1)
=[3(m+1) - 2m] / [ m(m+1)]
=(m+3) / [ m(m+1) ]
參考: A Sir
收錄日期: 2021-04-12 23:12:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070105000051KK01833