1. Peter work is a company at a starting monthly salary of $ 1000 and he receives an increase of $ 600 after each year.
a. What will Peter's monthly salary in the N^th Year?
b. What will the total amount which Peter Will earn during his first N^th year?
c. Tony works at the same time as Peter. His Starting monthly salary is $600 and he receives an increase of $100 after each year. After how many years will Tony's monthly salsry be equal to that of Peter?
數學問題一條....
2007-01-05 7:29 pm
回答 (3)
2007-01-05 7:45 pm
✔ 最佳答案
a)First year:1000Second year:1600
Third year:2200
Nth Year:100+(N-1)600
b)12*1000*N+12*600*N*(N-1)/2
C)Never,
600+100(N-1)=1000+600(N-1)
500+100N=400+600N
500N=100
N=0.2
Wrong Question?
Year 1 2 3 4 5 6
Peter 1000 1600 2200 2800 3400 4000
Tony 600 700 800 900 1000 1100
The difference is increasing
參考: ME
2007-01-05 9:28 pm
1(a).1000 + 600 x N
1(b)1000 + 600N
1(c)600 + 100Y = 1000 + 600N
100Y = 400 + 600N
Y = 4 + 1.5N (Have N because it is not a Variable!)
1(b)1000 + 600N
1(c)600 + 100Y = 1000 + 600N
100Y = 400 + 600N
Y = 4 + 1.5N (Have N because it is not a Variable!)
2007-01-05 7:44 pm
1a. Peter's monthly salary in the Nth year
1000+600^n
1b. Total amount earn during his first Nth year
[1000+600^(n-1)] * 12
1c. Never, as the Tony basic salary and the increase rate is less than Peter. And they both start together. So Tony's Monthly salary will never equal to Peter's.
1000+600^n
1b. Total amount earn during his first Nth year
[1000+600^(n-1)] * 12
1c. Never, as the Tony basic salary and the increase rate is less than Peter. And they both start together. So Tony's Monthly salary will never equal to Peter's.
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