一條簡單maths 題 10分

2007-01-05 6:50 am
用最簡單方法展開這個代數式


[ X (X) + 2X + 3 ] [X (X) + 2X + 3 ]

回答 (6)

2007-01-05 7:02 am
✔ 最佳答案
第一位答既方法係錯既
因為
題目要展開AND
(x+3)(x-1)=(x^2+2x-3)
?^2=?既二次方
so
(x(x)+2x+3)(x(x)+2x+3)
=(x^2+2x+3)(x^2+2x+3)
=x^4+2x^3++3x^2+2x^3+4x^2+6x+3x^2+6x+9
=x^4+4x^3+10x^2+12x+9
參考: me=]
2007-01-05 7:14 am
=(x^2+2x+3)(x^2+2x+3)
=x^4+2x^3+3x^2+2x^3+4x^2+6X+3x^2+6x+9
=(x^4)+(2x^3+2x^3)+(3x^2+4x^2+3x^2)+(6x+6x)+(9)
answer:
x^4+4x^3+10x^2+12x+9
2007-01-05 7:00 am
答案:2X四次+4X三次+10X二次+12X+9
2007-01-05 6:59 am
[X(X)+2X+3][X(X)+2X+3]
=[X(X)+2X+3]既2次方
=(X既2次方+2X+3)既2次方
=X既4次方+6X既3次方+2X既2次方+9

2007-01-04 23:14:01 補充:
OMG計錯左"上學期教的搵番本書....錯的- -"[ X (X) 2X 3 ] [X (X) 2X 3 ]=(X" 2X 3)"=X"" 4X"' 12X" 9第一個自乘第2個係第一個乘第二個再乘二第3個係第二個乘第三個再乖二第4個自乘OK?

2007-01-04 23:18:26 補充:
點解出唔到既- -再打多次= =[ X (X) 2X 3 ] [X (X) 2X 3 ]( X " 2X 3 ) "X"" 4X"' 12X 9

2007-01-04 23:21:25 補充:
點解咁既...算啦- -當我冇答過
2007-01-05 6:58 am
[ X (X) + 2X + 3 ] [X (X) + 2X + 3 ]

= (X^4+2X^3+3X^2+2X^3+4X^2+6X+3X^2+6X+9)
=X^4+4X^3+10X^2+12X+9
2007-01-05 6:56 am
[ X (X) + 2X + 3 ] [X (X) + 2X + 3 ]

(X+3)(X-1)(X+3)(X-1)

咁掛=.=

2007-01-04 23:35:00 補充:
dicksonmak2003 唔該你
參考: 我記憶


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