math question 2

2007-01-04 12:34 am
Steven bought a flat which was marked at $3200000 at a discount of 5%. He then sold it and made a profit of 20%.

(a). How much did Steven pay for the flat?
(b). How much did Steven sell the flat for?

( 必須有 算式 , 步驟 及 答案 )

回答 (4)

2007-01-04 12:48 am
✔ 最佳答案




Steven bought a flat which was marked at $3200000 at a discount of 5%. He then sold it and made a profit of 20%.

(a). How much did Steven pay for the flat?

Steven paid the flat for = Marked price x ( 1 - Discount % )



= $3200000 x ( 1 - 5% )
= $3200000 x 95 / 100
= $3040000


(b). How much did Steven sell the flat for?

Steven sold the flat for = The price he paid for it x ( 1 + Profit % )



= $3040000 x ( 1 + 20% )
= $3040000 x 120 /100
= $3648000




2007-01-04 5:43 am
(a). Steven paid:
$3200000*(1-5%)=$3200000*(100%-5%)=$3200000*95%=$3200000*0.95=$3040000

(b). Steven sold:
$3040000*(1+20%)=$3040000*(100%+20%)=$3040000*120%=3040000*1.2=$3648000
2007-01-04 12:47 am
a)
3,200,000 X (100 - 5)%
= 3,200,000 X 0.95
= 3,040,000
Steven paid $3,040,000 for the flat.

b)
3,040,000 X (100 + 20)%
= 3,040,000 X 1.2
= 3,648,000
Steven sold the flat for $3,648,000.
2007-01-04 12:45 am
a.以原本價錢獲取5%折扣,即是要付餘下95%
3200000 X 95%=3040000

b.以原本價錢多20%出售,即是原價100%+20%
3040000 X 120%=3648000


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