3ab+6bc
b)
2b(x-y)-a(x-y)
c)
a$-ab+ac-bc
$ = a 既 2 次 方
更新1:
「最佳回答」者: cwl808hk [小學級 4 級] &pppp_tng [小學級 5 級]
多項式分解為因式a-c題
回答 (4)
2007-01-04 12:31 am
a)
3ab+6bc
=3b(a+2c)
b)
2b(x-y)-a(x-y)
=(2b-a)(x-y)
c)
a$-ab+ac-bc
=a(a-b)+c(a-b)
=(a+c)(a-b)
3ab+6bc
=3b(a+2c)
b)
2b(x-y)-a(x-y)
=(2b-a)(x-y)
c)
a$-ab+ac-bc
=a(a-b)+c(a-b)
=(a+c)(a-b)
2007-01-04 12:26 am
a)
3ab+6bc
=3b(a+2c)
b)
2b(x-y)-a(x-y)
=(2b-a)(x-y)
c)
a$-ab+ac-bc
=a(a-b)+c(a-b)
=(a+c)(a-b)
3ab+6bc
=3b(a+2c)
b)
2b(x-y)-a(x-y)
=(2b-a)(x-y)
c)
a$-ab+ac-bc
=a(a-b)+c(a-b)
=(a+c)(a-b)
2007-01-04 12:14 am
a)
3ab+6bc
=3b(a+2c)
b)
2b(x-y)-a(x-y)
=x-y(2b-a)
=(x-y)(2b-a)
c)
a²-ab+ac-bc
=a(a-b)+c(a-b)
=(a+c)(a-b)
3ab+6bc
=3b(a+2c)
b)
2b(x-y)-a(x-y)
=x-y(2b-a)
=(x-y)(2b-a)
c)
a²-ab+ac-bc
=a(a-b)+c(a-b)
=(a+c)(a-b)
2007-01-04 12:14 am
因式分解時，加/減間抽同類項，括號當一項
a) 3ab + 6bc = 3a x b + 3a x 2c = 3a(b+2c)
b) 2b(x-y) - a(x-y) = (x-y)(2b-a)
c) a$-ab+ac-bc = a(a-b) + c(a-b) = (a-b)(a+c)
a) 3ab + 6bc = 3a x b + 3a x 2c = 3a(b+2c)
b) 2b(x-y) - a(x-y) = (x-y)(2b-a)
c) a$-ab+ac-bc = a(a-b) + c(a-b) = (a-b)(a+c)
收錄日期: 2021-04-30 21:46:51
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