解下列方程
22.7-4q/9=q/6+10
23.5x-12+4x-14-2x=23
24.0.4x+0.6x=0.8x+12
25.5(3x+1)=2(11-x)
26.2(4-2x)-15(2-x)=22
27.5(0.4-3)+7(1.5x-7)+4=2.5x
28.8[2(6x-4)-(4+3x)]=120+18x
29.7x/4+1=9x/8+11
30.x/3-20-x/7=10
31.2x-5/5+x+2/4=6
32.5x/3-2x+3/6=2/7-2x/3
數學問題(3)
2007-01-03 11:22 pm
回答 (1)
2007-01-03 11:38 pm
✔ 最佳答案
22. 7-4q/9=q/6+10-(4q/9)=q/6+3
-(24q/9) = q +18 (當你要乘6過對面既時侯, 3都要乘, 因為係成條數都要balance)
-(8q/3) = 18
- 8q = 54
q = -54/8 or -6.75
2007-01-03 15:48:51 補充：
23.5x-12+4x-14-2x=23 5x+4x-2x = 23+14+127x = 49 x=7 24.0.4x+0.6x=0.8x+12x - 0.8x = 12 (0.4 + 0.6 =1; 1x =x )0.2x = 12x = 6025)5(3x+1)=2(11-x)15x+15 = 22-22x 15x + 22x = 22 - 1537x = 7 x = 37/7
參考: me
收錄日期: 2021-04-12 23:20:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070103000051KK02029