我想將佢d左佢
應該點d
show step plz
更新1:
我既答案寫係=sqrt(sx+1)
更新2:
我既答案寫係=1/sqrt(2x+1)
一條數學題
回答 (3)
2007-01-03 1:44 am
✔ 最佳答案
開方(2x+1)=(2x+1)^1/2
=1/2log(2x+1)
If 開方(2x+1)=2
2x+1=2^2
2x+1=4
x=(4-1)/2
=3/2
2007-01-03 3:26 am
d開方(2x+1)/dx=d(2x+1)^(1/2)/dx
=(1/2)(2x+1)^(-1/2)(2)
=(2x+1)^(-1/2)
=1/sqrt(2x+1)
=(1/2)(2x+1)^(-1/2)(2)
=(2x+1)^(-1/2)
=1/sqrt(2x+1)
2007-01-03 1:36 am
4Xsq+4x +1 識唔識d, d by dx
收錄日期: 2021-04-24 08:38:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070102000051KK03284