✔ 最佳答案
Molar mass of Al2(SO4)3•6H2O = 2x27 + 3(32 + 4x16) + 6(2x1 + 16) = 450 g mol-1
No. of moles of Al2(SO4)3•6H2O = mass/(molar mass) = 67.5/450 = 0.15 mol
1. Each mol of Al2(SO4)3•6H2O contains 2 mol of Al3+ ions.
No. of moles of Al3+ ions = 2 x 0.15 = 0.3 mol
2. Each mol of Al2(SO4)3•6H2O contains 6 mol of H2O molecules.
No. of moles of H2O molecules = 6 x 0.15 = 0.9 mol
3. Each mol of Al2(SO4)3•6H2O contains 3 mol of S atoms.
No. of moles of S atoms = 3 x 0.15 = 0.45 mol
4. Each mol of Al2(SO4)3•6H2O contains 12 mol of 0 atoms.
No. of moles of 0 atoms = 12 x 0.15 = 1.8 mol
5. Each mol of Al2(SO4)3•6H2O contains 5 mol of ions (2 mol of Al3+ and 3 mol of SO42-).
No. of moles of ions = 5 x 0.15 = 0.75 mol
2007-01-02 12:32:23 補充:
Take L = 6.02 x 10^23 mol^-14. No. of O atoms = 1.8L = 1.08 x 10^255. No. of ions = 0.75L = 4.52 x 10^23
2007-01-02 12:34:20 補充:
Amendment of 4.4. No. of O atoms = 1.8L = 1.08 x 10^24