f.2數學,10分！

12Ax^2-24x+4Ax-8≡6x^2 +Bx +C

12Ax^2+(4A-24)x-8)≡6x^2 +Bx +C

12A=6----(1)

4A-24=B----(2)

C=-8

From (1):A=6/12
A=1/2 ----(3)

Put (3) into (2):4(1/2)-24=B
B= -22

(12x+4)(Ax-2)≡6x^2 +Bx +C

LHS=(12x+4)(Ax-2)
= 12Ax^2+(4A-24)x-8

because (12x+4)(Ax-2)≡6x^2 +Bx +C
therefore

12A=6
A=1/2

put A=1/2

4(1/2)-24=B
B=-22

and C=-8

A=1/2 B=(-22) C=(-8)
唔知岩唔岩...

把這些數分開便可求A、B和C的值