Maths Question [quick]

log{ (1.234x 5.678)^1000}
=1000 log(1.234x 5.678)
=1000x{ log1.234 + log5.678}
=1000x{ 0.0913 + 0.7541}
=1000x 0.8454
=8.454
=8 + 0.4 approx.
=8 + log2.512 approx.
Hence,
(1.234x 5.678)^1000
= 10^8 x 2.512
= 2.512 x10^8 approx.

2007-01-01 14:09:24 補充：
SORRY........=1000x 0.8454=845.4=845 0.4 =845 log2.512Hence,d=(1.234x 5.678)^1000= 10^845 x 2.512= 2.512 x10^845

2007-01-01 14:11:53 補充：
.....=1000x 0.8454=845.4=845 + 0.4=845 + log2.512=log ( 10^845 x 2.512)Hence,d=(1.234x 5.678)^1000= 10^845 x 2.512= 2.512 x10^845

d = (1.234 x 5.678)^1000
log d = 1000 log (1.234 x 5.678)
log d = 1000 log 1.234 + 1000 log 5.678
log d = 91.3 + 754.1
log d = 845.4
d = 10^(845.4)