f.2數.........急

2006-12-31 10:46 pm
因式分解:
-2(3x+4)=
(6-3x)(-8)=
(3x-2)(4)=
2(3x+4y)=
-2(3x-4y)=
3x(4x-5)=
(-7x)(-5x+8)=
6y(-3x-5y)=
(5x-2y)(-3x)=

回答 (6)

2006-12-31 10:51 pm
✔ 最佳答案
-2(3x+4)
=-6x-8

(6-3x)(-8)
=-48+24x

(3x-2)(4)
=12x-8

2(3x+4y)
=6x+8y

-2(3x-4y)
=-6x+4y

3x(4x-5)
=12x^2-15x

(-7x)(-5x+8)
=35x^2-56x

6y(-3x-5y)
=-18xy-30y^2

(5x-2y)(-3x)
=-15x^2=6xy

2006-12-31 14:53:02 補充:
最後那題錯左少少..應該係(5x-2y)(-3x)=-15x^2 6xy
參考: me
2007-01-12 3:16 am
咩叫"因式分解"... 錯左就錯左la
2007-01-05 5:05 am
-2(3x+4)= - 6 x - 8
(6-3x)(-8)= - 4 8 + 2 4 x
(3x-2)(4)= 1 2 x - 8
2(3x+4y)= 6 x + 8 y
-2(3x-4y)= - 6x + 8 y
3x(4x-5)= 1 2 x ^ 2 - 1 5 x
(-7x)(-5x+8)= 3 5 x ^ 2 - 5 6 x
6y(-3x-5y)= - 1 8 x y - 3 0 y ^ 2
(5x-2y)(-3x)= - 1 5 x ^ 2 + 6 x y

希望能help你~
以後有唔明e-mail俾我呀~
參考: 自己算
2006-12-31 10:56 pm
-2(3x+4)=-6x-8
(6-3x)(-8)=-42+24x
(3x-2)(4)=12x-8
2(3x+4y)=6x+8y
-2(3x-4y)=-6x+8y
3x(4x-5)=12x(2次方)-15x
(-7x)(-5x+8)=35x(2次方)-56x
6y(-3x-5y)=-18xy-30y(2次方)
(5x-2y)(-3x)=-35x(2次方)+6xy
2006-12-31 10:51 pm
你的問題本身就答案了!!!
-2(3x+4)
(6-3x)(-8)
(3x-2)(4)
2(3x+4y)
-2(3x-4y)
3x(4x-5)
(-7x)(-5x+8)
6y(-3x-5y)
(5x-2y)(-3x)
2006-12-31 10:51 pm
我用心算:
-2(3x+4)= -6x-8
(6-3x)(-8)= -48+24x
(3x-2)(4)= 12x-8
2(3x+4y)= 6x+8
-2(3x-4y)= -6x+8y
3x(4x-5)= 12x平方-15
(-7x)(-5x+8)= 35x平方-56
6y(-3x-5y)= -18xy-30y平方
(5x-2y)(-3x)= -15x平方+6xy
參考: 自己


收錄日期: 2021-04-12 21:37:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061231000051KK02198

檢視 Wayback Machine 備份