logx^2除log1/x是=幾?
回答 (2)
2006-12-31 4:11 am
✔ 最佳答案
logx^2=2logx (1)log1/x=logx^-1=-logx (2)
Therefore,
logx^2除log1/x=2logx除(-logx)
=-2
I hope you understand the logic or principle from the equation 1 and 2
That is, logx^y=ylogx
參考: My maths
2006-12-31 4:27 am
logx^2=2logx---------------------(1)
log1/x=logx^(-1)= -logx--------(2)
原式=1式除2式= -2
log1/x=logx^(-1)= -logx--------(2)
原式=1式除2式= -2
收錄日期: 2021-04-12 21:41:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061230000051KK03840