解 24(R)(1-R)=6
回答 (3)
2006-12-31 3:42 am
✔ 最佳答案
24r(1 - r) = 64r(1 - r) = 1
4r - 4r^2 = 1
4r^2 - 4r + 1 = 0
(2r - 1)^2 = 0
r = 1 / 2 (repeated)
2006-12-31 4:04 am
24(R)(1-R)=6
24R(1-R)=6
24R-24R^2=6
24R^2-24R+6=0
(6R-3)(4R-2)=0
(6R-3)=0 or (4R-2)=0
R=1/2 or R=1/2
(double root)
24R(1-R)=6
24R-24R^2=6
24R^2-24R+6=0
(6R-3)(4R-2)=0
(6R-3)=0 or (4R-2)=0
R=1/2 or R=1/2
(double root)
參考: myself
2006-12-31 3:54 am
24(R)(1-R) = 6
R(1-R) = 1/4
R - RxR = 1/4
0 = RxR - R + 1/4
0 = (R - 1/2)(R - 1/2)
R = 1/2 (repeated)
R(1-R) = 1/4
R - RxR = 1/4
0 = RxR - R + 1/4
0 = (R - 1/2)(R - 1/2)
R = 1/2 (repeated)
收錄日期: 2021-05-03 12:16:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061230000051KK03679