Quick math question

2006-12-30 3:11 pm
cos(x+y)=?
cos(x-y)=?
更新1:

tan(x+y) tan (x-y)

回答 (2)

2006-12-30 3:15 pm
✔ 最佳答案
cos(x+y)=cosxcosy-sinxsiny
cos(x-y)=cosxcosy+sinxsiny

2006-12-30 07:19:18 補充:
sin(-x) = -sin(x)csc(-x) = -csc(x)cos(-x) = cos(x)sec(-x) = sec(x)tan(-x) = -tan(x)cot(-x) = -cot(x) sin^2(x) + cos^2(x) = 1 tan^2(x) + 1 = sec^2(x) cot^2(x) + 1 = csc^2(x)

2006-12-30 07:19:58 補充:
sin(x+y) = sin x cos y + cos x sin y sin(x-y) = sin x cos y - cos x sin y cos(x+y) = cos x cosy - sin x sin y cos(x-y) = cos x cosy + sin x sin y tan(x+y) = (tan x + tan y) / (1- tan x tan y) tan(x-y) = (tan x - tan y) / (1+ tan x tan y)

2006-12-30 07:20:28 補充:
sin(2x) = 2 sin x cos x cos(2x) = cos^2(x) - sin^2(x) = 2 cos^2(x) - 1 = 1 - 2 sin^2(x) tan(2x) = 2 tan(x) / (1 - tan^2(x)) sin^2(x) = 1/2 - 1/2 cos(2x) cos^2(x) = 1/2 + 1/2 cos(2x)
2006-12-30 3:17 pm
cos(x+y)=cosxcosy-sinxsiny

cos(x-y)=cosxcosy+sinxsiny


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