[AL CHEM] Covalent bond --- Bond Angle of H20

2006-12-30 7:51 am
Explain why there is a slight increase in the bond angle (H - O - H) in water when the H3O^+ ion is formed.

回答 (1)

2006-12-31 10:33 am
✔ 最佳答案


圖片參考:http://upload.wikimedia.org/wikipedia/commons/thumb/5/50/Water-2D-labelled.png/160px-Water-2D-labelled.png

Diagram 1: Bond angle representation of water (H2O) [not showing two lone pairs of electron but they should be present]

圖片參考:http://upload.wikimedia.org/wikipedia/commons/thumb/4/43/Hydroxonium-cation.png/100px-Hydroxonium-cation.png

Diagram 2: 3-D schematic representation of hydronium ion (H3O+) showing one lone pair of electron

圖片參考:http://upload.wikimedia.org/wikipedia/commons/thumb/1/11/Ammonia-2D-dimensions.png/150px-Ammonia-2D-dimensions.png

Diagram 3: 3-D schematic representation of ammonia (NH3) showing one lone pair of electron

The bond angle (H - O - H) in water is smaller as it has two lone pairs of electrons (not shown in diagrams), which are 'bulky' and forced the H - O - H bond angle to restrain to a smaller angle.
In the case of hydronium ion, one of the two lone pairs is replaced by a O - H bond, thus leaving one lone pair left, as shown in Diagram 2, making it similar to ammonia in Diagram 3. Less number of 'bulky' lone pairs allow H - O - H bond angle to stretch out to a larger angle, and that is, the slight increase in bond angle mentioned.
參考: http://en.wikipedia.org/ (for diagrams only)


收錄日期: 2021-04-12 23:44:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061229000051KK04064

檢視 Wayback Machine 備份