我想問Maths題,題目:「0 - [2 - (3/2-2/3)]

:「0 - [2 - (3/2-2/3)]

先做分數相減

3/2 -2/3 = 9/6 - 4/6 = 5/6

之後是 2 - 5/6 = 12/6 -5/6 = 7/6

之後是 0 - 7/6 = -7/6 or 負1又6分之1

〔0-｛2-(3/2-2/3)〕=〔0-｛2-(9/6-4/6)〕
= 〔0-(2-5/6)
=｛0-1 又1/6)
= - 1又1/6

0-2-(5/6)
=-2-5/6
=-12/6-5/6
=-17/6