我想問Maths題,題目:「0 - [2 - (3/2-2/3)]
回答 (3)
2006-12-30 7:37 am
✔ 最佳答案
:「0 - [2 - (3/2-2/3)] 先做分數相減
3/2 -2/3 = 9/6 - 4/6 = 5/6
之後是 2 - 5/6 = 12/6 -5/6 = 7/6
之後是 0 - 7/6 = -7/6 or 負1又6分之1
2006-12-30 7:38 am
〔0-｛2-(3/2-2/3)〕=〔0-｛2-(9/6-4/6)〕
= 〔0-(2-5/6)
=｛0-1 又1/6)
= - 1又1/6
= 〔0-(2-5/6)
=｛0-1 又1/6)
= - 1又1/6
參考: myself
2006-12-30 7:33 am
0-2-(5/6)
=-2-5/6
=-12/6-5/6
=-17/6
=-2-5/6
=-12/6-5/6
=-17/6
收錄日期: 2021-04-12 19:09:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061229000051KK03966