2
a) Represent 6*10+0*10 +3*1 by a denary numeral.
b) Convert the denary numeral in 2
6*10+0*10 +3*1
into a hexadecimal number.
Maths Question
2006-12-28 9:09 am
回答 (1)
2006-12-28 9:36 am
✔ 最佳答案
2a)
6*10+0*10 +3*1
=60+0+3
=63
b)
63
=1*32+1*16+1*8+1*4+1*2+1
=111111(2) (a binary number)
ALSO
63
=3*16+15
=11F (16) (a hexadecimal number)
2006-12-28 01:37:51 補充：
最後應是3F
收錄日期: 2021-04-25 16:50:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061228000051KK00107