the angle ACB= 2 times angle ABC
angle BCA=3 times angle ACB
find the angle (degrees)
triangle
2006-12-28 12:43 am
回答 (2)
2006-12-28 12:59 am
✔ 最佳答案
Let angle ABC be xangle ACB = 2 angle ABC = 2x
angle BCA = 3 angle ACB = 3 (2x) = 6x
angle ABC + angle ACB + angle BCA = 180 deg (because angles of traingle)
x + 2x + 6x = 180deg
9x = 180deg
x = 20deg
so,
angle ABC = 20deg
angle ACB = 40deg
angle BCA = 120deg
參考: me
2006-12-28 12:56 am
你會唔會寫錯題目呀?!
angle BCA 理應等於 ANGLE ACB喎，
而且條問題都冇提供ANGLE CAB/ BAC的資料，
計唔到喎！
angle BCA 理應等於 ANGLE ACB喎，
而且條問題都冇提供ANGLE CAB/ BAC的資料，
計唔到喎！
收錄日期: 2021-04-12 23:01:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061227000051KK01406