a[b+c(x-T)]=(d)(e)(T-y)
T=???
Solve it step by step
Make the subject of the equation to be T
2006-12-26 12:29 am
回答 (5)
2006-12-26 3:00 am
a[b+c(x-T)]=(d)(e)(T-y)
ab+ac(x-T)=de(T-y)
ab+acx-acT=deT-dey
ab+acx+dey=deT+acT
T(ac+de)=ab+acx+dey
T=(ab+acx+dey)/(ac+de)
ab+ac(x-T)=de(T-y)
ab+acx-acT=deT-dey
ab+acx+dey=deT+acT
T(ac+de)=ab+acx+dey
T=(ab+acx+dey)/(ac+de)
參考: 自己
2006-12-26 12:51 am
a[b+c(x-T)]=(d)(e)(T-y)
ab+ac(x-T)=de(T-y)
ab+acx-acT=deT-dey
ab+acx+dey=deT+acT
T(ac+de)=ab+acx+dey
T=(ab+acx+dey)/(ac+de)
ab+ac(x-T)=de(T-y)
ab+acx-acT=deT-dey
ab+acx+dey=deT+acT
T(ac+de)=ab+acx+dey
T=(ab+acx+dey)/(ac+de)
2006-12-26 12:40 am
a[b+c(x-T)]=(d)(e)(T-y)
a(b+cx-cT)=de(T-y)
ab+acx-acT=deT-dey
ab+acx+dey=deT+acT
ab+acx+dey=T(de+ac)
(ab+acx+dey)/(de+ac)=T
T=(ab+acx+dey)/(de+ac
a(b+cx-cT)=de(T-y)
ab+acx-acT=deT-dey
ab+acx+dey=deT+acT
ab+acx+dey=T(de+ac)
(ab+acx+dey)/(de+ac)=T
T=(ab+acx+dey)/(de+ac
2006-12-26 12:35 am
a[b+c(x-T)]=(d)(e)(T-y)
ab+ac(x-T)=deT-dey
ab+acx-acT=deT-dey
ab+acx+dey=deT+acT
deT+acT=ab+acx+dey
T(de+ac)=(ab+acx+dey)
T=(ab+acx+dey)/(de+ac)
ab+ac(x-T)=deT-dey
ab+acx-acT=deT-dey
ab+acx+dey=deT+acT
deT+acT=ab+acx+dey
T(de+ac)=(ab+acx+dey)
T=(ab+acx+dey)/(de+ac)
2006-12-26 12:34 am
a[b+c(x-T)]=(d)(e)(T-y)
ab+ac(x-T)=deT-dey
ab+acx+dey=deT+acT
ab+acx+dey=T(de+ac)
T=(ab+acx+dey)/(de+ac)
ab+ac(x-T)=deT-dey
ab+acx+dey=deT+acT
ab+acx+dey=T(de+ac)
T=(ab+acx+dey)/(de+ac)
收錄日期: 2021-04-12 21:27:23
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https://hk.answers.yahoo.com/question/index?qid=20061225000051KK02275