The mass of hot soup is 0.3 kg . The specific heat capacity and temperature of the soup are 3600 J kg-1'C-1 and 90'C respectively . How much water at 2'C should be added to lower the temperature of the soup to 30'C ?
The soup changes from 90oC to 30oC; The water changes from 2oC to 30oC.
Energy released by soup = 0.3 x 3600 x (90-30) = 64800 J
Energy absorbed by water = m x 4200 x (30-2) = 117600m J
Energy absorbed by water = Energy released by soup
117600m = 64800
Hence, m = 0.551
The mass of water required = 0.551 kg