factorize
(x^2+y^2-2xy)+(x-y-6)
factorize
2006-12-24 2:48 am
回答 (5)
2006-12-24 3:50 am
✔ 最佳答案
( x^2 + y^2 - 2xy ) + ( x - y - 6 )=( x - y )^2 + ( x - y ) - 6
=( x - y - 2 ) ( x - y +3 ) (ANS.)
2006-12-23 20:22:57 補充：
Take x - y = z, we have( x^2 + y^2 - 2xy ) + ( x - y - 6 )=( x - y )^2 + ( x - y ) - 6=z^2 + z - 6=( z - 2) ( z +3)=( x - y - 2 ) ( x - y +3 ) (ANS.)Common mistake:(x-y)^2 + (x-y-6) = (x-y)(x-y-6)which is absolutely incorrect.
2006-12-24 8:18 am
(x^2+y^2-2xy) + (x-y-6)
= (x-y)^2 + (x-y) - 6
= [(x-y) +3] [(x-y) -2]
= (x-y+3)(x-y-2)
= (x-y)^2 + (x-y) - 6
= [(x-y) +3] [(x-y) -2]
= (x-y+3)(x-y-2)
參考: correct choice!
2006-12-24 4:31 am
(x^2+y^2-2xy) + (x-y-6)
= (x-y)^2 + (x-y) - 6
= [(x-y) +3] [(x-y) -2]
= (x-y+3)(x-y-2)
= (x-y)^2 + (x-y) - 6
= [(x-y) +3] [(x-y) -2]
= (x-y+3)(x-y-2)
參考: myself
2006-12-24 3:16 am
factorize
(x^2+y^2-2xy)+(x-y-6)
=x^2+y^2-2xy)+x-y-6
=x^2+x+y^2-y-2xy-6
=x(x+1)+y(y-1)-2(xy-3),,
(x^2+y^2-2xy)+(x-y-6)
=x^2+y^2-2xy)+x-y-6
=x^2+x+y^2-y-2xy-6
=x(x+1)+y(y-1)-2(xy-3),,
收錄日期: 2021-04-12 21:21:47
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