解答下la~! 要詳細> <
化算下列各式.
1) (5a^5)(4a^4)
2) 2(a)(a^3)
3) 2(2a^3)(4a^2)
4) 4a^5/8a^2
5) 4a^5/6a^2
6) 10a^7/25a^4
7) (a^2)^4
8) (x^a)^b
9) (a^x)^9
10) (2ab)^4
11) (2/b)^4
12) (a^3/b^5)^4
數學一問~! help
2006-12-24 12:53 am
回答 (3)
2006-12-24 1:17 am
✔ 最佳答案
1) (5a^5)(4a^4)= (5 x 4) a^(5+4)
=20a^9
2) 2(a)(a^3)
= 2a^(1+3)
= 2a^4
3) 2(2a^3)(4a^2)
= (2 x 2 x 4) a^(3+2)
= 16a^5
4) 4a^5/8a^2
= a^5/2a^2
= a^(5-2)/2
= a^3 / 2
5) 4a^5/6a^2
= 2a^5/3a^2
= 2a^(5-2) / 3
= 2a^3 / 3
6) 10a^7 / 25a^4
= 2a^7 / 5a^4
= 2a^(7-4) / 5
= 2a^3 / 5
7) (a^2)^4
= a^(2x4)
= a^8
8) (x^a)^b
= x^(ab)
9) (a^x)^9
= a^(9x)
10) (2ab)^4
= 2^4 x a^4 x b^4
= 16a^4b^4
11) (2/b)^4
= 2^4 / b^4
= 16 / b^4
12) (a^3/b^5)^4
= a^(3x4) / b^(5x4)
= a^12 / b^20
2006-12-24 1:08 am
1)
(5a^5)(4a^4)
= 20a^9
2)
2(a)(a^3)
= 2a^4
3)
2(2a^3)(4a^2)
= 16a^5
4)
4a^5/8a^2
= 32a^7
5)
4a^5/6a^2
= 24a^7
6)
10a^7/25a^4
= (2a^3)/5
7)
(a^2)^4
= a^8
8)
(x^a)^b
= x^(ab)
9)
(a^x)^9
= a^(9x)
10)
(2ab)^4
= 16 a^4 b^4
11)
(2/b)^4
= 16/b^4
12)
(a^3/b^5)^4
= a^12/b^20
(5a^5)(4a^4)
= 20a^9
2)
2(a)(a^3)
= 2a^4
3)
2(2a^3)(4a^2)
= 16a^5
4)
4a^5/8a^2
= 32a^7
5)
4a^5/6a^2
= 24a^7
6)
10a^7/25a^4
= (2a^3)/5
7)
(a^2)^4
= a^8
8)
(x^a)^b
= x^(ab)
9)
(a^x)^9
= a^(9x)
10)
(2ab)^4
= 16 a^4 b^4
11)
(2/b)^4
= 16/b^4
12)
(a^3/b^5)^4
= a^12/b^20
2006-12-24 1:05 am
1) (5a^5)(4a^4)
=20a^9
2) 2(a)(a^3)
=2a^4
3) 2(2a^3)(4a^2)
=16a^5
4) 4a^5/8a^2
=a^3/2
5) 4a^5/6a^2
=24a^7
6) 10a^7/25a^4
=2a^3/5
7) (a^2)^4
=a^8
8) (x^a)^b
=x^(ab)
9) (a^x)^9
=a^(9x)
10) (2ab)^4
=16a^4b^4
11) (2/b)^4
=16/b^4
12) (a^3/b^5)^4
=a^12/b^20
=20a^9
2) 2(a)(a^3)
=2a^4
3) 2(2a^3)(4a^2)
=16a^5
4) 4a^5/8a^2
=a^3/2
5) 4a^5/6a^2
=24a^7
6) 10a^7/25a^4
=2a^3/5
7) (a^2)^4
=a^8
8) (x^a)^b
=x^(ab)
9) (a^x)^9
=a^(9x)
10) (2ab)^4
=16a^4b^4
11) (2/b)^4
=16/b^4
12) (a^3/b^5)^4
=a^12/b^20
收錄日期: 2021-04-12 21:59:47
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https://hk.answers.yahoo.com/question/index?qid=20061223000051KK02681