因式分解
(x+y)*z*-4(x+y)(x-y)z*+4(x-y)*z*
*=2次方
MATHs十萬火急
2006-12-21 4:20 am
回答 (2)
2006-12-21 4:32 am
(x+y)*z*-4(x+y)(x-y)z*+4(x-y)*z*
=z*[(x+y)*-4(x+y)(x-y)+4(x-y)*]
=z*[(x+y) - 2(x-y)]*
=z*[x+y - 2x+2y][x+y + 2x-2y]
=z*(3y-x)(3x-y)
*=2次方
=z*[(x+y)*-4(x+y)(x-y)+4(x-y)*]
=z*[(x+y) - 2(x-y)]*
=z*[x+y - 2x+2y][x+y + 2x-2y]
=z*(3y-x)(3x-y)
*=2次方
2006-12-21 4:28 am
(x+y)*z* - 4(x+y)(x-y)z* + 4(x+y)*z*
= z*(x+y)[(x+y)-4(x-y) + 4]
= z*(x+y)(-3x + 5y + 4 )
= z*(x+y)[(x+y)-4(x-y) + 4]
= z*(x+y)(-3x + 5y + 4 )
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061220000051KK03269