已知m,n是ax^2+bx+c=0的根
即是ax^2+bx+c=a(x-m)(x-n)
點解ax^2+bx+c=a(x-m)(x-n)?????
咁(x-m)(x-n)唔係=ax^2+bx+c=0嫁咩
我唔明點解ax^2+bx+c=a(x-m)(x-n)
以唔係ax^2+bx+c=(x-m)(x-n)
個a點樣得黎嫁
收錄日期: 2021-04-26 14:27:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061219000051KK03754