S.1 Maths (Please)

你是否要展開式 (expansion)?
(1) 3x(x-2y+4)

3x(x-2y+4)
= 3x(x) + 3x(-2y) + 3x(4)
= 3x² - 6xy + 12x
============================
(2) -2y(2x+2y-3)

-2y(2x+2y-3)
= -2y(2x) - 2y(2y) - 2y(-3)
= -4xy - 4y² + 6x
============================
(3) -y(2x+3y-5z)

-y(2x+3y-5z)
= -y(2x) - y(3y) -y(-5z)
= -2xy - 3y² + 5yz

============================
(4) (3x-5y+3)(-2x)

(3x-5y+3)(-2x)
= 3x(-2x) - 5y(-2x) + 3(-2x)
= -6x² + 10xy - 6x

============================
(5) (4x-2y-3z)(-z)

(4x-2y-3z)(-z)
= 4x(-z) - 2y(-z) - 3z(-z)
= -4xz + 2yz + 3z²

============================
(6) (4x-2y+7z)(-x)

(4x-2y+yz)(-x)
= 4x(-x) -2y(-x) + yz(-x)
= -4x² + 2xy - xyz

============================
(7) 2x(x²+2xy-3y²)

2x(x²+2xy-3y²)
= 2x(x²) + 2x(2xy) + 2x(-3y²)
= 2x³ + 4x²y - 6xy²

============================
(8) 3y(x²+2xy-4)

3y(x²+2xy-4)
= 3y(x²) + 3y(2xy) + 3y(-4)
= 3x²y + 6xy² - 12y

(1)3x(x-2y+4)=3x(2次)-6xy+12x
(2)-2y(2x+2y-3)=-4xy-4y(2次)+6y
(3)-y(2x+3y-5z)=-2xy-3y(2次)+5yz
(4)(3x-5y+3)(-2x)=-6x(2次)+10xy-6x
(5) (4x-2y-3z)(-z)=-4xz+2yz+3z(2次)
(6)(4x-2y+7z)(-x)=-4x(2次)+2xy-7xz
(7) 2x(x２次+2xy-3y２次)=2x(3次)+2x(2次)y-6xy(2次)
(8) 3y(x２次+2xy-4)=3x(2次)y+6xy(2次)-12y

一定啱!!
希望你選擇我做最佳回答!!!thank you
希望你選擇我做最佳回答!!!thank you
希望你選擇我做最佳回答!!!thank you
一定啱!!