a + 5 - 6 = 11
a = ???
I want to ask how to 計......
2006-12-20 1:32 am
回答 (9)
2006-12-25 1:20 am
+5-6=11
a-1=11
a=11+1
a=12
2006-12-25 16:38:09 補充：
a+5-6=11a-1=11a=11+1a=12
a-1=11
a=11+1
a=12
2006-12-25 16:38:09 補充：
a+5-6=11a-1=11a=11+1a=12
2006-12-20 1:50 am
a+5-6=11
a+5-6+6=11+6-------把11+上6
a+5-5=17-5
a=12
or
a+5-6=11
a-1=11------算式+5-6
a-1+1=11+1
a=12
a+5-6+6=11+6-------把11+上6
a+5-5=17-5
a=12
or
a+5-6=11
a-1=11------算式+5-6
a-1+1=11+1
a=12
2006-12-20 1:43 am
a+5-6=11
a+5=11+6
a+5=17
a=17-5
a=12
a+5=11+6
a+5=17
a=17-5
a=12
2006-12-20 1:43 am
最重要明白'='的重要性，是两边所做的动作必须一样
a + 5 - 6 = 11
=> a + (-1) = 11
=> a - 1 = 11
两边同时'+1'
=> a - 1 + 1 = 11 + 1
=> a = 12
a + 5 - 6 = 11
=> a + (-1) = 11
=> a - 1 = 11
两边同时'+1'
=> a - 1 + 1 = 11 + 1
=> a = 12
2006-12-20 1:35 am
a + 5 - 6 = 11
a + 5 = 11 + 6
a + 5 = 17
a = 17 - 5
a = 12
a + 5 = 11 + 6
a + 5 = 17
a = 17 - 5
a = 12
2006-12-20 1:35 am
a = 11 - 5 + 6
a = 12
a = 12
2006-12-20 1:35 am
a+5-6=11
a-1=11
a=11+1
a=12
a-1=11
a=11+1
a=12
收錄日期: 2021-04-18 20:29:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061219000051KK02161