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A 2 by n “chessboard” is to be covered by two types of tiles, 2 by 1 and 2 by 2. As an
illustration, four of the 21 possible ways of covering a 2 by 5 chessboard are shown
below.
Show by Mathematical induction that the number of ways of covering a 2 by n “chessboard” by 2 by 1 tiles and 2 by 2 tiles is
1/3 (2^n+1 + (-1^n))
Hint: induction step is (P(k – 1) AND P(k – 2)) -->P(k).
It is a very tough MI question, can you please explain how to prove it step by step , please