十大難題之(一)

2006-12-19 3:00 am
1.m+y=h+t+(a÷500)
hX(e+a)=2000000000000000000
y+a÷0.584=8321.8321
mX(m+y)=400a
那麼a+e(y+2000000000000000000)=a?

回答 (1)

2006-12-22 11:26 am
✔ 最佳答案
先分解一些式...
y+a÷0.584=8321.8321
y+a=8321.8321*0.584
y+a=4859.9499464
y=4859.9499464-a

mX(m+y)=400a
m^2X+mXy=400a
m^2X+mX(4859.9499464-a)=400a
m^2X+4859.9499464mX-mXa=400a
m^2X+4859.9499464mX=(400+mX)a
a=m^2X+4859.9499464mX/(400+mX)


a+e(y+2000000000000000000)
=a+e(y+hX(e+a)) -------------------------->(as hX(e+a)=2000000000000000000)
=a+ey+hXe^2+ehXa
=a+e(4859.9499464-a)+hXe^2+ehXa -------------------------->(y=4859.9499464-a)
=m^2X+4859.9499464mX/(400+mX)+4859.9499464e-(m^2X+4859.9499464mX/(400+mX))e+hXe^2+ehX(m^2X+4859.9499464mX/(400+mX))

我計不下去了....
只有一條式有e...根本解不了吧...///

我估答案=2a
參考: 自己


收錄日期: 2021-04-12 18:21:59
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