〔(35-A)×1/3〕×3＋2/3×(35-A)×4＋2A=90
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2006-12-19 1:55 am
回答 (2)
2006-12-19 2:08 am
✔ 最佳答案
[(35-A) x 1/3] x3 + 2/3 x (35-A)x4 + 2A = 90(35-A) + 8/3 (35-A) + 2A = 90
3(35-A) + 8(35-A) + 6A = 270
105 - 3A + 280 - 8A + 6A = 270
- 5A = -115
A = 23
2006-12-18 23:26:20 補充：
下面既朋友，您拆 2/3 x (35-A) x 4 呢 part漏左 2/3x35 都要 x4 喎.您再check下啦~ ^^
2006-12-19 2:44 am
〔(35-A)×1/3〕×3＋2/3×(35-A)×4＋2A=90
(35/3 -A/3)×3+70/3-2A/3×4+2A=90
35-A+70/3-2A/3×4+2A=90
3(35-A+70/3-2A/3×4+2A)=270
3×35-3A+70-2A×12+6A=270
105-3A+70-2A×12+6A=270
-3A-2A×12+6A=270-70-105
-3A-24A+6A=95
-21A=95
A=-4 11/21
(35/3 -A/3)×3+70/3-2A/3×4+2A=90
35-A+70/3-2A/3×4+2A=90
3(35-A+70/3-2A/3×4+2A)=270
3×35-3A+70-2A×12+6A=270
105-3A+70-2A×12+6A=270
-3A-2A×12+6A=270-70-105
-3A-24A+6A=95
-21A=95
A=-4 11/21
收錄日期: 2021-04-18 20:29:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061218000051KK02547