F.2 maths Q

simplify this expression

x+4y/-2x(x-2y)+1/3x

x+4y/-2x(x-2y)+1/3x
=(x+4y/-2x(x-2y)+1/3x)*3x
=3x2+12xy/-2x(x-2y)+1
=(3x2+12xy/-2x(x-2y)+1)*-2x(x-2y)
=-6x3(x-2y)+12xy-2x(x-2y)
=-6x4+12x3y+12xy-2x2+4xy
=-6x4+12x3y-2x2+12xy+4xy
=-6x4+12x3y-2x2+16xy
答案根據x的冪排列








2006-12-17 19:35:58 補充：
最尾仲可以多一步~就係抽個2出黎=-6x^4 12x^3y-2x^2 16xy=2(-2x^4 6x^3y-x^2 8xy)

x+4y/-2x(x-2y)+1/3x
=x+12y/-2X(x-2y)+X
=-2x(x-2y)x+12y+x[-2x(x-2y)]
=-2x^3+4x^2y+12y-2x^3+4x^2y
=-4x^3+8x^2y+12y

2006-12-21 15:43:01 補充：
疑錯左= =".....