✔ 最佳答案
Take 2^b =3 .
b is irrational otherwise there exits non-zero m and n such that 2^m = 3^n.
b is irrational and hence b and 1 are linearly independent over rational.
According to the (Theorem 2.4) below, b is not algebraic irrational otherwise the number 3 is transcendental !!!
This means that b is transcendental and hence b is not rational number.
2006-12-17 07:34:06 補充:
SORRY{{ Take 2^b =3 .b is irrational otherwise there exits non-zero m and n such that 2^m = 3^n. }}The above statement is enough. Just forget the nonsense following it and please forgive me about that. I have been confusing it with another question.
2006-12-17 07:36:35 補充:
Please forgive me about not deleting this answer.I just want to keep some record for my work even this is very foolish work.
2006-12-23 20:32:20 補充:
It is very lucky to be selected because I answered the question in a very dreadful way.
參考: Transcendental Number Theory, by Alan Baker, p11, (Theorem 2.4)