數學問題....20分!!!!!!快!
回答 (6)
2006-12-17 7:10 am
✔ 最佳答案
a^4+B^4=(a^2)^2-[-(B^2)^2]
=(a^2)^2-[-1*(B^2)^2]
=(a^2+iB^2)(a^2-iB^2)
i=(-1)^0.5虛數單位
2006-12-16 23:22:04 補充：
另一個~a^4+B^4=a^4-[-(B^4)]=a^4-(-1*B^4)=(a-√i*B)(a^3+a^2*√i*B+aiB^2+i√iB^3)=(a-√0.5*(1+i)*B)(a^3+a^2*√0.5(1+i)*b+aiB^2+i√0.5(1+i)B^3)√i=√0.5+i√0.5fromx^4-y^4=(x-y)(x^3+x^2y+xy^2+y^3)
2006-12-22 5:20 am
(a+B)的次...方, Yes and No?
2006-12-18 1:20 am
a^4 + B^4
=(a+B)(a^3-a^2B-aB^2+B^3)
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I hope I can help you
=(a+B)(a^3-a^2B-aB^2+B^3)
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I hope I can help you
2006-12-17 6:37 am
a^4+b^4
=(a^2)^2 + (b^2)^2
=(a^2+b^2)^2 -2(a^2)(b^2)
請問你條問題係想問a=幾同埋b=幾, 定係咩呢?
同埋, 會唔會係a^4 + B^4=0 的解呢??
如果係=0, 會有唔同解法
2006-12-16 22:38:49 補充：
對於上面lydia_sai的答法絕對錯= =千其唔好俾佢誤導a^4+b^4點會等於(a+b)^4= ="
=(a^2)^2 + (b^2)^2
=(a^2+b^2)^2 -2(a^2)(b^2)
請問你條問題係想問a=幾同埋b=幾, 定係咩呢?
同埋, 會唔會係a^4 + B^4=0 的解呢??
如果係=0, 會有唔同解法
2006-12-16 22:38:49 補充：
對於上面lydia_sai的答法絕對錯= =千其唔好俾佢誤導a^4+b^4點會等於(a+b)^4= ="
2006-12-17 6:36 am
(a+B)既四次方
2006-12-17 6:33 am
a^4 + B^4
收錄日期: 2021-04-12 21:29:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061216000051KK04859