√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+……=?
注意: √4+√4...唔係指2+2(因為我唔想打括號),我的意思係 請把√4+√4變成√(4+√4)....
開方問題~~~~~
2006-12-16 2:28 am
回答 (2)
2006-12-16 2:43 am
✔ 最佳答案
x² = 4+xx = √(4+x)
=√(4+√(4+√(4+√...
So √4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4...
is the root of the equation
x² = 4+x
x² - x - 4 =0
x = 1±√[(-1)² - 4(1)(-4)] / 2(1)
=(1±√17 ) / 2
but √4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4...
is positive
so √4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4+√4...
=(1+√17 ) / 2
2006-12-16 2:31 am
√40000000000000000000
收錄日期: 2021-04-12 22:29:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061215000051KK02641